Answer
$\frac{15}{2x}$
Work Step by Step
($\frac{2x}{3y}$) $\times$ ($\frac{5y}{x}$) $\times$ ($\frac{9}{4x}$) =
Multiply the numerators by each other, and multiply the denominators by each other
$\frac{2x\ \times\ 5y\ \times\ 9}{3y\ \times\ x\ \times\ 4x}$ =
Factor the numerator and the denominator
$\frac{2\ \times\ x\ \times\ 5\ \times\ y\ \times\ 3\ \times\ 3}{3\ \times\ y\ \times\ x\ \times\ 2\ \times\ 2\ \times\ x}$ =
Cancel the common factors between the numerator and the denominator to obtain:
$\frac{5\ \times\ 3\ }{2 \times x}$ =
$\frac{15}{2x}$
