Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1 - Page 48: 46

Answer

$-\dfrac{2xw}{3yz}$

Work Step by Step

First, cancel common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{3}x}{\cancel{4}y} \cdot \dfrac{-\cancel{8}2w}{\cancel{9z}3} \\=\dfrac{x}{y} \cdot \dfrac{-2w}{3z}$ Multiply the numerators together and the denominators together to obtain: $=\dfrac{-2xw}{3yz} \\=-\dfrac{2xw}{3yz}$
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