Answer
$\dfrac{8}{21}$
Work Step by Step
First, factor each expression to obtain:
$=\dfrac{6a}{2b(7)} \cdot \dfrac{2b(8)}{6a(3)}$
Cancel the common factors to obtain:
$\require{cancel}
=\dfrac{\cancel{6a}}{\cancel{2b}(7)} \cdot \dfrac{\cancel{2b}(8)}{\cancel{6a}(3)}
\\=\dfrac{1}{7} \cdot \dfrac{8}{3}$
Multiply the numerators together and the denominators together to obtain:
$=\dfrac{8}{21}$
