Answer
$\dfrac{3}{5}$
Work Step by Step
Cancelling the common factor between the numerator and the denominator, the given expression, $
\dfrac{15y}{25y}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{5y}\cdot3}{\cancel{5y}\cdot5}
\\\\=
\dfrac{3}{5}
\end{array}
