Chapter 2 - Real Numbers - 2.1 - Rational Numbers: Multiplication and Division - Problem Set 2.1 - Page 48: 7

$-\dfrac{1}{6}$

Cancelling the common factor between the numerator and the denominator, the given expression, $ \dfrac{-8}{48} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{-8}}{\cancel{-8}\cdot(-6)} \\\\= \dfrac{1}{-6} \\\\= -\dfrac{1}{6} \end{array}