Answer
$\lim\limits_{x\to7}(x-4)^3=27.$
Work Step by Step
By Theorem $1.5: \lim\limits_{x\to c}(f(g(x)))=f(\lim\limits_{x\to c}g(x)).$
$\lim\limits_{x\to7}(x-4)^3=(\lim\limits_{x\to7}(x-4))^3=(7-4)^3=27.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 16
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