Answer
$\lim\limits_{x\to-2}\dfrac{x+2}{x^2-4}=-\dfrac{1}{4}.$
Work Step by Step
$\lim\limits_{x\to-2}\dfrac{x+2}{x^2-4}=\lim\limits_{x\to-2}\dfrac{(x+2)}{(x-2)(x+2)}$
$=\lim\limits_{x\to-2}\dfrac{1}{(x-2)}=\dfrac{1}{-2-2}=-\dfrac{1}{4}.$
N.B: Possible typo in book where the variables are not the same; in this solution $x$ was used.
