Answer
$\lim\limits_{x\to6^-}\dfrac{x-6}{x^2-36}=\dfrac{1}{12}.$
Work Step by Step
$\lim\limits_{x\to6^-}\dfrac{x-6}{x^2-36}=\lim\limits_{x\to6^-}\dfrac{(x-6)}{(x-6)(x+6)}=\lim\limits_{x\to6^-}\dfrac{1}{x+6}$
$=\dfrac{1}{6^-+6}=\dfrac{1}{12}.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 40
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