Answer
Finding the distance along the line can be solved using precalculus.
$d=\sqrt{68}$
Work Step by Step
Using the distance formula:
$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$
$d=\sqrt{(3-1)^2+(9-1)^2}$
$d=\sqrt{2^2+8^2}$
$d=\sqrt{4+64}$
$d=\sqrt{68}$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 2
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