Answer
$\lim\limits_{x\to0}\dfrac{[1/(x+1)]-1}{x}=1.$
Work Step by Step
$\lim\limits_{x\to0}\dfrac{[1/(x+1)]-1}{x}=\lim\limits_{x\to0}\dfrac{1-(x+1)}{x(x+1)}=\lim\limits_{x\to0}-\dfrac{1}{x+1}=\dfrac{-1}{0+1}=-1.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - Review Exercises - Page 91: 23
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
