Answer
a) $0.283$ million Internet users per
b) the rate of change decreases
c) $0.35$ million Internet users per year
d) the rate of change at t = 2002 is greater than the average rate of change R
Work Step by Step
a) (2002, 3.75) (2005, 4.6)
$\frac{ΔN}{Δt}$ = $\frac{4.6-3.75}{2005-2002}$ = $0.283$ million Internet users per year
b) slope decrease so the rate of change decreases as t increase
c) (2001, 3.1) (2005, 4.5)
$\frac{ΔN}{Δt}$ = $\frac{4.5-3.1}{2005-2001}$ = $0.35$ million Internet users per year
d) slope decrease so the rate of change at t = 2002 is greater than the average rate of change R
