Answer
$f’(3) = 30$
Work Step by Step
$f(x) = 5x^{2}$
$f’(3) = \lim\limits_{h \to 0} \frac{f(3+h)-f(3)}{h} = \lim\limits_{h \to 0} \frac{45 + 30h +5h^2-(5\times9)}{h}$
$f’(3) = \lim\limits_{h \to 0} \frac{45 + 30h +5h^2-45}{h}$
$f’(3) = \lim\limits_{h \to 0} \frac{30h +5h^2}{h}$
$f’(3) = \lim\limits_{h \to 0}{30 +5h}$
$f’(3) = 30 $
