Answer
$f’(2) = 13 $
Work Step by Step
$f(x) = x^2 +9 $
$f’(2) = \lim\limits_{h \to 0}{\frac{f(2+h)-f(2)}{h}} $
$ f’(2) = \lim\limits_{h \to 0} \frac{(2+h)^2 +9(2+h) -22}{h} $
$ f’(2) = \lim\limits_{h \to 0} \frac{13h+h^2}{h} $
$ f’(2) = \lim\limits_{h \to 0}(13 + h) $
$ f’(2) = 13 $
