Answer
$f’(1) = 5 $
Work Step by Step
$f(x) = x^3 +2x $
$ f’(1) = \lim\limits_{h \to 0}{\frac{f(1+h) - f(1)}{h}} $
$ f’(1) = \lim\limits_{h \to 0} \frac{(1+h)^3 + 2(1+h) -(1^3+2)}{h} $
$f’(1) = \lim\limits_{h \to 0} \frac{h^3+3h^2+5h}{h} $
$f’(1) = \lim\limits_{h \to 0} h^2 +3h +5 $
$f’(1) = 5 $