Answer
$f’(-1) = -2 $
Work Step by Step
$f(x)= 3x^2 + 4x +2 $
$ f’(-1) = \lim\limits_{h \to 0} \frac{f(-1+h) - f(-1)}{h} $
$ f’(-1) = \lim\limits_{h \to 0} \frac{3(-1+h)^2+4(-1+h) +2 -1}{h} $
$ f’(-1) = \lim\limits_{h \to 0} \frac{3h^2-2h}{h} $
$f’(-1) = \lim\limits_{h \to 0} (3h-2) $
$f’(-1) = -2 $
