Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 19

Answer

$x^{4}-4x^{3}+6x^{2}-4x+1$

Work Step by Step

$(x^{2}-2x+1)^{2}=(x^{2}-2x+1)(x^{2}-2x+1)$ $=x^{2}(x^{2}-2x+1)-2x(x^{2}-2x+1)+1(x^{2}-2x+1)$ $=x^{4}-2x^{3}+x^{2}-2x^{3}+4x^{2}-2x+x^{2}-2x+1$ $=x^{4}-4x^{3}+6x^{2}-4x+1$
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