Answer
$y=3$ or $y=-\frac{1}{3}$
Work Step by Step
$3y^{2}-8y-3$
=$3y^{2} - 9y + y -3$
=$3y(y-3)+1(y-3)$
$(y-3)(3y+1)$$=0$
$y=3$ or $y=-\frac{1}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 40
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