Answer
x=$-\frac{3}{4}$ or $x=\frac{2}{3}$
Work Step by Step
$12x^{2}+x-6$
=$12x^{2}+9x-8x-6$
=$23x(4x+3)-2(4x+3)$
$(4x+3)(3x-2)$$=0$
x=$-\frac{3}{4}$ or $x=\frac{2}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 43
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