Answer
y=$-\frac{3}{2}$ or $x=-\frac{4}{3}$
Work Step by Step
$6y^{2}+17y+12$
=$6y{2}+8y+9y+12$
=$2y(3y+4)+3(3y+4)$
$(2y+3)(3y+4)$$=0$
y=$-\frac{3}{2}$ or $x=-\frac{4}{3}$
Finite Math and Applied Calculus (6th Edition)
by Waner, Stefan; Costenoble, Steven
Published by
Brooks Cole
ISBN 10:
1133607705
ISBN 13:
978-1-13360-770-0
Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 42
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