Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 0 - Section 0.3 - Multiplying and Factoring Algebraic Expressions - Exercises - Page 21: 28

Answer

$(x^2+1)\sqrt{x+1}-\sqrt{(x+1)^3}=x(x-1)\sqrt{x+1}$

Work Step by Step

$(x^2+1)\sqrt{x+1}-\sqrt{(x+1)^3}$ $(x^2+1)\sqrt{x+1}-\sqrt{(x+1)^2(x+1)}=(x^2+1)\sqrt{x+1}-(x+1)\sqrt{x+1}$ $(x^2+1-(x+1))\sqrt{x+1}=(x^2-x)\sqrt{x+1}=x(x-1)\sqrt{x+1}$
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