Answer
$x=2$ or $x=-\frac{1}{2}$
Work Step by Step
$2x^{2}-3x-2$
=$2x^{2} - 4x + x -2$
=$2x(x-2)+1(x-2)$
$(x-2)(2x+1)$$=0$
$x=2$ or $x=-\frac{1}{2}$
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