Chapter 10 - Parametric Equations and Polar Coordinates - 10.4 Exercises - Page 693: 42

Thus the points of intersection are: $(\frac{1}{\sqrt[4]{2}}, \pi/8), (\frac{1}{\sqrt[4]{2}}, 9\pi/8)$

$sin2\theta=cos2\theta$ $\theta=\frac{\pi}{8},\frac{9\pi}{8}$ Thus the points of intersection are: $(\frac{1}{\sqrt[4]{2}}, \pi/8), (\frac{1}{\sqrt[4]{2}}, 9\pi/8)$