Answer
$16x^4-96x^3y+216x^2y^2-216xy^3+81y^4 $
Work Step by Step
Use the formula, we have $(2x-3y)^4=\binom 4 0(2x)^4 + \binom 4 1(2x)^3(-3y) + \binom 4 2(2x)^2(-3y)^2 +\binom 4 3(2x)(-3y)^3 +\binom 4 4(-3y)^4 =16x^4-96x^3y+216x^2y^2-216xy^3+81y^4 $
