Answer
(a) $\frac{1}{26}$
(b) $\frac{10}{13}$
(c) $\frac{4}{13}$
(d) 3 to 10.
Work Step by Step
(a) There are two red 3's, thus $P=\frac{2}{52}=\frac{1}{26}$
(b) There are 12 face cards, not a face card is the complement, thus $P=1-\frac{12}{52}=\frac{10}{13}$
(c) There are 13 spades including one king and 3 other kings, thus $P=\frac{13+3}{52}=\frac{4}{13}$
(d) The probability of drawing a face card is $P=\frac{12}{52}=\frac{3}{13}$, thus the odds in favor of drawing a face card (vs not a face card) is $\frac{\frac{3}{13}}{\frac{10}{13}}$ or 3 to 10.
