Answer
$60w^4y^2$
Work Step by Step
Use the formula, we have $(w-2y)^6=\binom 6 0(w)^6 + \binom 6 1(w)^5(-2y) + \binom 6 2(w)^4(-2y)^2 +...$, thus the third term is $\binom 6 2(w)^4(-2y)^2=60w^4y^2$
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