Precalculus (6th Edition)

by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie

Published by Pearson

ISBN 10: 013421742X

ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Test - Page 1085: 17

Answer

$35$

Work Step by Step

$C(7,3)=\frac{7!}{3!(7-3)!}=\frac{7!}{3!(4)!}=\frac{7(6)(5)}{3(2)(1)}=35$

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