Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Test - Page 1085: 4

Answer

$49$

Work Step by Step

1. Given arithmetic sequence with $a_1=1, a_3=25$, we have $a_3=a_1+(3-1)d$ or $25=1+2d$, thus $d=12$ 2. We have $a_5=a_1+(5-1)d=1+4(12)=49$
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