Precalculus (6th Edition)

by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie

Published by Pearson

ISBN 10: 013421742X

ISBN 13: 978-0-13421-742-0

Chapter 11 - Further Topics in Algebra - Test - Page 1085: 5

Answer

$-\frac{32}{3}$

Work Step by Step

Given geometric sequence with $a_1=81, r=-\frac{2}{3}$, we have $a_6=a_1r^{6-1}=81(-\frac{2}{3})^5=-\frac{32}{3}$

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