Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 100

Answer

$\frac{n^{1/2}}{5m^{5/2}}$

Work Step by Step

$(\frac{25m^3n^5}{m^{-2}n^6})^{-1/2}= (25m^{3+2}n^{5-6})^{-1/2}= (25m^{5}n^{-1})^{-1/2}=25^{-1/2}m^{-5/2}n^{1/2}=\frac{n^{1/2}}{5m^{5/2}}$
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