Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 114

Answer

$ \frac{7+\sqrt 3}{20}$

Work Step by Step

$\frac{2}{7-\sqrt 3}=\frac{2}{7-\sqrt 3}\times\frac{7+\sqrt 3}{7+\sqrt 3}=\frac{2(7+\sqrt 3)}{49-9}=\frac{7+\sqrt 3}{20}$
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