Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 87

Answer

$$\frac{16}{25}$$

Work Step by Step

Remember that with negative exponents: $a^{-n} = \frac{1}{a^{n}}$ $(\frac{x}{y})^{-n}=\frac{y^{n}}{x^{n}}$ so... $(-\frac{5}{4})^{-2}=(-\frac{4}{5})^{2}$ $(-\frac{4}{5})(-\frac{4}{5})=\frac{16}{25}$ $$\frac{16}{25}$$
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