Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 101

Answer

$\frac{1}{p^2q^4}$

Work Step by Step

$\frac{(p^{15}q^{12})^{-4/3}}{(p^{24}q^{16})^{-3/4}}=\frac{p^{-20}q^{-16}}{p^{-18}q^{-12}}=p^{-20+18}q^{-16+12}=p^{-2}q^{-4}=\frac{1}{p^2q^4}$
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