Answer
$\frac{1}{p^2q^4}$
Work Step by Step
$\frac{(p^{15}q^{12})^{-4/3}}{(p^{24}q^{16})^{-3/4}}=\frac{p^{-20}q^{-16}}{p^{-18}q^{-12}}=p^{-20+18}q^{-16+12}=p^{-2}q^{-4}=\frac{1}{p^2q^4}$
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