Answer
$ \frac{6(3+\sqrt 2)}{7}$
Work Step by Step
$\frac{6}{3-\sqrt 2}=\frac{6}{3-\sqrt 2}\times\frac{3+\sqrt 2}{3+\sqrt 2}=\frac{6(3+\sqrt 2)}{9-2}=\frac{6(3+\sqrt 2)}{7}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - Chapter R Test Prep - Review Exercises - Page 84: 115
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