Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 49

Answer

$x^{2}-x+2$

Work Step by Step

First, distribute the sign located between the two polynomials to the second polynomial. Since it is a positive, none of the signs will change. After distribution, it will remain the same: $$(5x^{2}-4x+7)+(-4x^{2}+3x-5)$$ . After distribution, the parenthesis can be dropped so that you are left with: $$5x^{2}-4x+7-4x^{2}+3x-5$$ Then simply combine like terms. The squareds with the squareds, etc. $$x^{2}-x+2$$
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