Answer
$r^4+12r^3+54r^2+108r+81$
Work Step by Step
Use the formula $(a+b)^2=a^2+2ab+b^2$ , we have:
$(r+3)^4=(r+3)^2(r+3)^2=(r^2+6r+9)^2=[(r^2+6r)+9]^2=(r^2+6r)^2+2(r^2+6r)(9)+81=r^4+12r^3+36r^2+18r^2+108r+81=r^4+12r^3+54r^2+108r+81$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 86
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