Answer
$6m^5+\frac{1}{4}m^4-\frac{1}{8}m^3$
Work Step by Step
$m^3(2m-\frac{1}{4})(3m+\frac{1}{2})=\frac{1}{8}m^3(8m-1)(6m+1)=\frac{1}{8}m^3(48m^2+8m-6m-1)=\frac{1}{8}m^3(48m^2+2m-1)=6m^5+\frac{1}{4}m^4-\frac{1}{8}m^3$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 58
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