Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 68

Answer

$t^4-32t^2+256$

Work Step by Step

Use the formula $(a+b)(a-b)=a^2-b^2$, we have $(t+4)(t+4)(t-4)(t-4)=(t+4)(t-4)[(t+4)(t-4)]=(t^2-16)(t^2-16)=(t^2-16)^2=t^4-32t^2+256$
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