Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises - Page 33: 84

Answer

$z^3-9z^2+27z-27$

Work Step by Step

Use the formula $(a-b)^3=a^3-3a^2b+3ab^2-b^3$ , we have: $(z-3)^3=z^3-3z^2(3)+3z(3)^2-(3)^3=z^3-9z^2+27z-27$
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