Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 103

Answer

$\frac{-7+2\sqrt {14}+\sqrt 7-2\sqrt 2}{2}$

Work Step by Step

Multiply $\frac{2\sqrt 7-4\sqrt 2}{2\sqrt 7-4\sqrt 2}$ to the expression, we have: $\frac{\sqrt 7-1}{2\sqrt 7+4\sqrt 2}\cdot \frac{2\sqrt 7-4\sqrt 2}{2\sqrt 7-4\sqrt 2}=\frac{14-4\sqrt {14}-2\sqrt 7+4\sqrt 2}{28-32}=\frac{14-4\sqrt {14}-2\sqrt 7+4\sqrt 2}{-4}=\frac{-7+2\sqrt {14}+\sqrt 7-2\sqrt 2}{2}$
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