Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 107

Answer

$\frac{3m(2-\sqrt {m+n})}{4-m-n}$

Work Step by Step

Multiply $\frac{2-\sqrt {m+n}}{2-\sqrt {m+n}}$ to the expression, we have: $\frac{3m}{2+\sqrt {m+n}}\cdot \frac{2-\sqrt {m+n}}{2-\sqrt {m+n}}=\frac{3m(2-\sqrt {m+n})}{4-m-n}$
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