Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 106

Answer

$3+\sqrt r$

Work Step by Step

Multiply $\frac{3+\sqrt r}{3+\sqrt r}$ to the expression, we have: $\frac{9-r}{3-\sqrt r}\cdot \frac{3+\sqrt r}{3+\sqrt r}=\frac{(9-r)(3+\sqrt r)}{9-r}=3+\sqrt r$
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