Answer
$\frac{a(\sqrt {a+b}+1)}{a+b-1}$
Work Step by Step
Multiply $\frac{\sqrt {a+b}+1}{\sqrt {a+b}+1}$ to the expression, we have:
$\frac{a}{\sqrt {a+b}-1}\cdot \frac{\sqrt {a+b}+1}{\sqrt {a+b}+1}=\frac{a(\sqrt {a+b}+1)}{a+b-1}$
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