Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 108

Answer

$\frac{a(\sqrt {a+b}+1)}{a+b-1}$

Work Step by Step

Multiply $\frac{\sqrt {a+b}+1}{\sqrt {a+b}+1}$ to the expression, we have: $\frac{a}{\sqrt {a+b}-1}\cdot \frac{\sqrt {a+b}+1}{\sqrt {a+b}+1}=\frac{a(\sqrt {a+b}+1)}{a+b-1}$
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