Answer
$-12^{\circ}F$
Work Step by Step
Given $T_w=35.74+0.6215T-35.75V^{0.16}+0.4275TV^{0.16}$, for $T=10^{\circ}F, V=30 mph$, we have:
$T_w=35.74+0.6215(10)-35.75(30)^{0.16}+0.4275(10)(30)^{0.16}\approx-12^{\circ}F$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter R - Review of Basic Concepts - R.7 Radical Expressions - R.7 Exercises - Page 76: 113
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