Answer
- $ \frac{3\sqrt 3}{2} $
or $ - \frac{3}{2} \sqrt 3 $
Work Step by Step
Given expression
= -3 $\sin2x$
= -3 $\sin2 (30^{\circ})$
( replacing $ x$ with $ 30^{\circ}$)
= -3 $\sin60^{\circ}$
= -3 $ \times (\frac{\sqrt 3}{2})$
( substituting exact value of $\sin 60^{\circ}$)
= - $ \frac{3\sqrt 3}{2} $
or $ - \frac{3}{2} \sqrt 3 $
