Answer
$ \frac{1}{\sqrt 3}$
Work Step by Step
To find out exact value of $ \cot 60^{\circ}$, considering special triangle- $ 30^{\circ} - 60^{\circ} - 90^{\circ}$
$\cot 60^{\circ}$ = $\frac{side - adjacent - 60^{\circ}}{side - opposite - 60^{\circ}}$
$\cot 60^{\circ}$ = $ \frac{1}{\sqrt 3}$
=$ \frac{1}{\sqrt 3}$
