Answer
2
Work Step by Step
To find out exact value of $ \sec 60^{\circ}$, considering special triangle- $ 30^{\circ} - 60^{\circ} - 90^{\circ}$
$\sec 60^{\circ}$ = $\frac{hypotenuse}{side - adjacent - 60^{\circ}}$
$\sec 60^{\circ}$ = $ \frac{2}{1}$
= 2
