Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 2 - Section 2.1 - Definition II: Right Triangle Trigonometry - 2.1 Problem Set - Page 63: 69

Answer

sin$\angle$FCH = $\frac{1}{\sqrt 3}$ cos $\angle$FCH = $\frac{\sqrt 2}{\sqrt 3}$

Work Step by Step

CH=$\sqrt CD^{2} + DH^{2}$ =$\sqrt 5^{2}+ 5^{2}$ =5$\sqrt 2$ CF=$\sqrt CH^{2} + HF^{2}$ =$\sqrt (5\sqrt 2)^{2}+ 5^{2}$ =5$\sqrt 3$ sin$\angle$FCH= $\frac{HF}{CF}$ = $\frac{5}{5\sqrt 3}$ = $\frac{1}{\sqrt 3}$ cos $\angle$FCH= $\frac{CH}{CF}$ = $\frac{5\sqrt 2}{5\sqrt 3}$ = $\frac{\sqrt 2}{\sqrt 3}$
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