Answer
We consider the reaction,
ATP + creatine phosphocreatine + ADP
We know that delta Go for this reaction is 12.6 kJ/mol delta G for the reaction = delta Gº + RT In ([phosphocreatine] [ADP] / [ATP] [creatine]) => delta G = (12.6) + (8.314 x 298) x In (2.5 x 0.15 / 4 x 1)) / 1000 => delta G = 12.6 - 5.9 6.7 kJ / mol = delta G for the reverse reaction will be - 6.7 kJ/mol We know that the reaction is favoured in the direction for which delta G is negative. => Reaction will proceed in the opposite direction, i.e in the direction of ATP synthesis.
Work Step by Step
We consider the reaction,
ATP + creatine phosphocreatine + ADP
We know that delta Go for this reaction is 12.6 kJ/mol delta G for the reaction = delta Gº + RT In ([phosphocreatine] [ADP] / [ATP] [creatine]) => delta G = (12.6) + (8.314 x 298) x In (2.5 x 0.15 / 4 x 1)) / 1000 => delta G = 12.6 - 5.9 6.7 kJ / mol = delta G for the reverse reaction will be - 6.7 kJ/mol We know that the reaction is favoured in the direction for which delta G is negative. => Reaction will proceed in the opposite direction, i.e in the direction of ATP synthesis.
