Answer
1) We know that free energy change( delta G) of a reaction and eqilibirum constant(K) satisfy Delta G= -RT* InK where T is in Kelvin ==>> InK= -(delta G)/RT = 31500/8.314*310 = 12.22 >> K= 2.1*10^5 2) YES this reaction to serve as a control point for its pathway (the citric acid cycle).
Work Step by Step
1) We know that free energy change( delta G) of a reaction and eqilibirum constant(K) satisfy Delta G= -RT* InK where T is in Kelvin ==>> InK= -(delta G)/RT = 31500/8.314*310 = 12.22 >> K= 2.1*10^5 2) YES this reaction to serve as a control point for its pathway (the citric acid cycle).
