Answer
A) Glycogen----3 G1P (by glycogen phosphorylase) 3 G1P -3 G6P (by phosphoglucomutase) From G6P to 2 pyruvate, input 1 ATP (by phosphofuctoase kinase) output 4 ATP Net yield 3 ATP Thus, from 3 residue of glycogen to 6 pyruvate: 3 x 3 = 9 ATP. (+9).
(B)Stage I, input2 ATP per glucose Stage II: output 4 ATP per glucose Net yield is 2 ATP per glucose. Thus, 3 glucose to 6 pyruvate will be 6 ATP.(+6).
(C) 2 pyruvate to 1 glucose costs 6 ATP: 2 each at the steps catalyzed by pyruvate carboxylase;PEPCK and phosphoglycerate kinaseThus, 6 pyruvate to 3 glucose needs 18 ATP input(-18).
Work Step by Step
A) Glycogen----3 G1P (by glycogen phosphorylase) 3 G1P -3 G6P (by phosphoglucomutase) From G6P to 2 pyruvate, input 1 ATP (by phosphofuctoase kinase) output 4 ATP Net yield 3 ATP Thus, from 3 residue of glycogen to 6 pyruvate: 3 x 3 = 9 ATP. (+9).
(B)Stage I, input2 ATP per glucose Stage II: output 4 ATP per glucose Net yield is 2 ATP per glucose. Thus, 3 glucose to 6 pyruvate will be 6 ATP.(+6).
(C) 2 pyruvate to 1 glucose costs 6 ATP: 2 each at the steps catalyzed by pyruvate carboxylase;PEPCK and phosphoglycerate kinaseThus, 6 pyruvate to 3 glucose needs 18 ATP input(-18).
